2009-03-26 13 views

Odpowiedz

20
tup = (2009, 3, 23, 13, 6, 34, 0, 82, 0) 
import datetime 
d = datetime.datetime(*(tup[0:6])) 
#two equivalent ways to format it: 
dStr = d.isoformat(' ') 
#or 
dStr = d.strftime('%Y-%m-%d %H:%M:%S') 
+0

Doskonale, dziękuję. – NeonNinja