Mam bazę danych ze schematem public
i schema_A
. Muszę utworzyć nowy schemat schema_b
o tej samej strukturze co schema_a
. Znalazłem funkcję poniżej, problem polega na tym, że nie kopiuje ograniczeń klucza obcego.Jak duplikować schematy w PostgreSQL
CREATE OR REPLACE FUNCTION clone_schema(source_schema text, dest_schema text)
RETURNS void AS
$BODY$
DECLARE
object text;
buffer text;
default_ text;
column_ text;
BEGIN
EXECUTE 'CREATE SCHEMA ' || dest_schema ;
-- TODO: Find a way to make this sequence's owner is the correct table.
FOR object IN
SELECT sequence_name::text FROM information_schema.SEQUENCES WHERE sequence_schema = source_schema
LOOP
EXECUTE 'CREATE SEQUENCE ' || dest_schema || '.' || object;
END LOOP;
FOR object IN
SELECT table_name::text FROM information_schema.TABLES WHERE table_schema = source_schema
LOOP
buffer := dest_schema || '.' || object;
EXECUTE 'CREATE TABLE ' || buffer || ' (LIKE ' || source_schema || '.' || object || ' INCLUDING CONSTRAINTS INCLUDING INDEXES INCLUDING DEFAULTS)';
FOR column_, default_ IN
SELECT column_name::text, REPLACE(column_default::text, source_schema, dest_schema) FROM information_schema.COLUMNS WHERE table_schema = dest_schema AND table_name = object AND column_default LIKE 'nextval(%' || source_schema || '%::regclass)'
LOOP
EXECUTE 'ALTER TABLE ' || buffer || ' ALTER COLUMN ' || column_ || ' SET DEFAULT ' || default_;
END LOOP;
END LOOP;
END;
$BODY$ LANGUAGE plpgsql
Jak można sklonować/skopiować schema_A
z zagranicznymi kluczowych ograniczeń?
Jeśli chcesz sklonować schemat za pomocą zapytania SQL, sprawdź [to] (https://stackoverflow.com/questions/2370614/copy-schema-and-create-new-schema-with-different-name- w tej samej bazie danych/48732283 # 48732283). – IdanDavidi