2013-04-29 12 views

Odpowiedz

4
select distinct 
    object_name(fic.[object_id])as table_name, 
    [name] 
from 
    sys.fulltext_index_columns fic 
    inner join sys.columns c 
     on c.[object_id] = fic.[object_id] 
     and c.[column_id] = fic.[column_id] 
25

Oto jak je zdobyć

SELECT 
    t.name AS TableName, 
    c.name AS FTCatalogName , 
    i.name AS UniqueIdxName, 
    cl.name AS ColumnName 
FROM 
    sys.tables t 
INNER JOIN 
    sys.fulltext_indexes fi 
ON 
    t.[object_id] = fi.[object_id] 
INNER JOIN 
    sys.fulltext_index_columns ic 
ON 
    ic.[object_id] = t.[object_id] 
INNER JOIN 
    sys.columns cl 
ON 
     ic.column_id = cl.column_id 
    AND ic.[object_id] = cl.[object_id] 
INNER JOIN 
    sys.fulltext_catalogs c 
ON 
    fi.fulltext_catalog_id = c.fulltext_catalog_id 
INNER JOIN 
    sys.indexes i 
ON 
     fi.unique_index_id = i.index_id 
    AND fi.[object_id] = i.[object_id]; 
+1

to zapytanie jest lepiej, ponieważ zawiera 'fulltext_catalogs.name' –

+0

wygląda jak http://dba.stackexchange.com/a/31651/14672;) – NateJ